CQI ASQ Certified Quality Inspector Practice Questions
Prepare for CQI with more than an answer.
- Exam fee
- $460 USD
- Level
- Professional
- Valid for
- Lifetime
Domains covered on the exam 4
- Technical Mathematics19%
- Metrology26%
- Inspection and Test32%
- Quality Assurance and Improvement23%
- 1
A manufacturing process utilizes an automated compensation equation to adjust tool offset. The equation provided by engineering is 4x - 0.015 = 0.045, where 'x' represents the required tool offset in inches. What is the correct value for x?
Show answer details
Correct answer: A
To solve the first-degree equation 4x - 0.015 = 0.045, first add 0.015 to both sides: 4x = 0.060. Then divide both sides by 4: x = 0.015.
- 2
A quality inspector measures five consecutive parts from a machining center and records the following diameters in millimeters: 12.4, 12.6, 12.5, 12.5, 12.8. What are the median and mode of this data set, respectively?
Show answer details
Correct answer: A
To find the median, arrange the numbers in numerical order: 12.4, 12.5, 12.5, 12.6, 12.8. The middle number is 12.5. The mode is the number that appears most frequently, which is also 12.5.
- 3
During a first-article inspection, a critical dimension is found to have shifted from its original prototype value of 2.500 inches to 2.445 inches. What is the percent change of this dimension from the prototype stage?
Show answer details
Correct answer: A
The percent change formula is: ((New Value - Original Value) / Original Value) * 100. Plugging in the numbers: ((2.445 - 2.500) / 2.500) * 100 = (-0.055 / 2.500) * 100 = -0.022 * 100 = -2.20%.
- 4
A quality inspector must verify the volume of a cylindrical fluid reservoir to ensure it meets the minimum capacity requirement of 120.0 cubic centimeters. The reservoir has an internal diameter of 4.0 cm and an internal height of 10.0 cm. What is the calculated volume of the reservoir?
Show answer details
Correct answer: A
The formula for the volume of a cylinder is V = π × r² × h. Since the diameter is 4.0 cm, the radius (r) is 2.0 cm. V = 3.14159 × (2.0)² × 10.0 = 3.14159 × 4.0 × 10.0 = 125.66 cubic centimeters.
